The number of integral values of k for which the equation  7 cosx + 5 sinx = 2k + 1 has a solution is

The number of integral values of k for which the equation  7 cosx + 5 sinx = 2k + 1 has a solution is

  1. A

    4

  2. B

    8

  3. C

    12

  4. D

    10

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    Solution:

    The range of 7cosx+5sinx is

    72+52,72+52=[74,74]742k+174k=0,1,2,3,1,2,3,4

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