Solution:
We have f(x) = x3 + ax2 + bx + c and g(x) = x2 + 1Dividing f(x) by g(x)
⇒ f(x) = g(x)(x + a) + (b – 1)x + (c – a) and
if f(x) is divisible by g(x):
⇒ (b – 1)x + (c – a) = 0
⇒ b – 1 = 0 and c – a = 0
⇒ b = 1 and c = a
As a and c related to {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
then a and c can be choose in 10 ways
10 possible polynomial are formed.
Hence option (1) is correct.