The number of values of k for which the system of linear equations,(k+2)x+10y=kkx+(k+3)y=k−1 has no solution is :

The number of values of k for which the system of linear equations,

(k+2)x+10y=k

kx+(k+3)y=k1 has no solution is :

  1. A

    infinitely many

  2. B

    1

  3. C

    2

  4. D

    3

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    Solution:

    Given equations will have no solution if

    k+2k=10k+3kk1

    On solving first two, we have

    (k+2)(k+3)=10kk25k+6=0k=2,3

    For k=2 these equations are identical.

    So, for only k = 3 these equations have no solution 

    There is only one value of k.

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