The number of values of k for which the system of equations: (k+1)x+8y=4k,kx+(k+ 3)y=3k-1   has no solution, is  

The number of values of k for which the system of

 equations: (k+1)x+8y=4k,kx+(k+ 3)y=3k-1   has no 

solution, is  

  1. A

    infinite  

  2. B

    1

  3. C

    2

  4. D

    3

    Register to Get Free Mock Test and Study Material

    +91

    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    The given system of equations will have no

      solution if

     k+1k=8k+34k3k1

     k+1k=8k+3 and  8k+34k3k1

      k2+4k+3=8k  and  24k84k2+12k

     k24k+3=0  and 4k212k+80

     k=1,3  and  k23k+20k=3 

    Hence, there is only one value of  k

    Chat on WhatsApp Call Infinity Learn

      Register to Get Free Mock Test and Study Material

      +91

      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.