The number of values of k for which the system of equations: (k+1)x+8y=4k,kx+(k+ 3)y=3k-1   has no solution, is

# The number of values of k for which the system of equations:    has no solution, is

1. A

infinite

2. B

1

3. C

2

4. D

3

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### Solution:

The given system of equations will have no

solution if

$\frac{k+1}{k}=\frac{8}{k+3}\ne \frac{4k}{3k-1}$

and

and

and $4{k}^{2}-12k+8\ne 0$

and

Hence, there is only one value of  $k$

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