The number of ways of selecting 4 cards of an ordinary pack of playing cards so that exactly 3 of themare of the same denomination is

The number of ways of selecting 4 cards of an ordinary pack of playing cards so that exactly 3 of them
are of the same denomination is

  1. A

    2496

  2. B

     13C3×4C3×48

  3. C

     52C3×48

  4. D

    none of these

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    Solution:

    We can choose one denomination in  13C1 ways, then 3 cards of this denomination can be chosen

    in  4C3 ways and one remaining card can be chosen in  48C1 ways. Thus, the total number of choices is

     13C1 4C3 48C1=13×4×48=2496.

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