MathematicsThe paint in a certain container is sufficient to paint an area equal to 9.375  m 2  . How many bricks of dimensions 22.5 cm × 10 cm × 7.5 cm can be painted out of this container?

The paint in a certain container is sufficient to paint an area equal to 9.375  m 2  . How many bricks of dimensions 22.5 cm × 10 cm × 7.5 cm can be painted out of this container?


  1. A
    200
  2. B
    100
  3. C
    300
  4. D
    400 

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    Solution:

    We consider that the paint in a certain container is sufficient to paint an area equal to 9.375. The dimensions of the brick are 22.5 cm x 10 cm x 7.5 cm.
    The length of the l brick is therefore 22.5 cm, the width of the b brick is 10 cm and the height of the h brick is 7.5 cm. The brick will look like this:
    IMG_256
    We need to paint each face of the brick. Therefore, the area to be painted in one brick will be equal to its area. We can find the area of ​​a cuboid brick by the relationship given by the formula,
     SA = 2 lb + bh + hl  SA = 2(22.5 × 10 + 10 × 7.5 + 22.5 ×7.5)  SA = 2 225 + 75 + 168.75  SA = 2 468.75    SA = 937.5   
    Now we need to find out how many of these bricks with an area of ​​937.5 can make a total area of ​​9.375But the units of total area are .
    We need to convert the total area to units of square cm.
    We know that 1 m = 100 cm. We will align both sides.

    Thus,
     Now, to find out the number of bricks that can be painted, we need to find the ratio of the total area that can be painted to the surface area of ​​one brick.
     No of bricks = 93750c m 2 937.5 m 2  
     No of bricks = 100.
    Hence, 100 bricks can be painted with the available paint.
     
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