The quartile deviation for the datax    :      2      3      4       5      6f    :        3      4      8       4     1 is 

The quartile deviation for the data

x    :     2     3     4       5      6f    :        3     4     8       4    1 is 

  1. A

    12

  2. B

    1

  3. C

    14

  4. D

    0

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    Solution:

    Computation of Q1 and Q3:

          xfc.f.233347481554196120 N=20 

    We have, N=20

     N4=5 and 3N4=15

    We observe that the cumulative frequencies just greater than N4(=5) and 3N4(=15) are 7 and 19 respectively. The

    corresponding values of X are 3 and 5 respectively.

     Q1=3 and Q3=5

    Hence,  Q.D. =12Q3Q1=1

     

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