MathematicsThe simplest form of 3525 is

The simplest form of $\sqrt[5]{352}$ is

A
$3 \sqrt[5]{11}$
B
$2 \sqrt[5]{11}$
C
$4 \sqrt[5]{11}$
D
$5 \sqrt[5]{4}$

Solution:

$\sqrt[5]{352} = \sqrt[5]{2^{5} \times 11}$

$= 2 \times \sqrt[5]{11}$

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