The slope of the tangent at (1,6) on the curve 2×2+3y2=110 is

The slope of the tangent at (1,6) on the curve $2 x^{2} + 3 y^{2} = 110 i s$

A
-9
B
-1/9
C
1/9
D
9

Solution:

$\frac{d y}{d x} = \frac{- 4 x}{6 y} a n d s l o p e o f \tan g e n t a t (1, 6) i s \frac{- 1}{9}$

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