The slope of the tangent at (1,6) on the curve 2×2+3y2=110  is

The slope of the tangent at (1,6) on the curve 2x2+3y2=110  is

  1. A

    -9

  2. B

    -1/9

  3. C

    1/9

  4. D

    9

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    Solution:

     dydx=-4x6y and slope of tangent at 1,6 is -19   

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