The smallest positive x satisfying logCosxSinx+logSinxCosx=2 is

The smallest positive x satisfying $\log_{C o s x} S i n x + \log_{S i n x} C o s x = 2$ is

A
$\frac{π}{2}$
B
$\frac{π}{3}$
C
$\frac{π}{4}$
D
$\frac{π}{6}$

Solution:

$\sin x = \cos x$

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