The sum of the mean and variance of a binomial distribution is 15 and the sum of their squares is 117. The mean of the distribution is

# The sum of the mean and variance of a binomial distribution is 15 and the sum of their squares is 117. The mean of the distribution is

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### Solution:

Let n and p be parameters of the binomial distribution. Then,

[Given]

and $p=\frac{1}{3}$

Hence, mean = np = 9.

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