MathematicsThe sum of the real roots of the equation isClass:  10

The sum of the real roots of the equation is


Class:  10


  1. A
    6
  2. B
    1
  3. C
    0
  4. D
    –4 

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    Solution:

    Given,
    ⇒ x[(–3x)(x + 2) – (2x)(x – 3)] – (–6)[(2)(x + 2) – (–3)(x – 3)] – 1[(2)(2x) – (–3x)(3)] = 0
    ⇒ x(– 3x2 – 6x – 2x2 + 6x) + 6(2x + 4 +3x – 9) – 1(4x – 9x)
    ⇒ x(–5x2) + 6(5x – 5) – 1(–5x)
    ⇒ –5x3 + 30x – 30 + 5x = 0
    ⇒ –5x3 + 35x – 30 = 0
    ⇒ x3 – 7x + 6 = 0
    ⇒ (x + 1)(x – 2)(x – 3)
    x = 1, 2, –3
    Therefore all roots are real
    So, sum of roots = 1 + 2 – 3 = 0
      
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