The sum of the roots of the equation x2+px+q=0 is equal to the sum of their squares, then

The sum of the roots of the equation x2+px+q=0 is equal to the sum of their squares, then

  1. A

    p2q2=0

  2. B

    p2+q2=2q

  3. C

    p2+p=2q

  4. D

    q2+q=2p

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    Solution:

    x2+px+q=0

    as per sum

    α+β=α2+β2

    α+β=(α+β)22αβ

    p=(p)22q

    p2+p=2q

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