MathematicsThe sum of two numbers is 99. If one number is 20%  more than the other; find the two numbers.

The sum of two numbers is 99. If one number is 20%  more than the other; find the two numbers.


  1. A
    45 & 33
  2. B
    54 & 45
  3. C
    66 & 35
  4. D
    63 & 65 

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    Solution:

    Let, the first number be a, so second number be b = 99 - a.
    As per the question,
    a = b + 20% of b
    a = 99 - a + 20100 (99 - a)
    a = 99 - a + 19.8 - 0.2a
    2.2a = 118.8
    a = 118.82.2
    a = 54
    so second number be b 99 - 54 = 45.
    The two numbers are 54 and 45.
     
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