MathematicsThe sum of 12,13 and 17 is

The sum of $\frac{1}{2}, \frac{1}{3}$ and $\frac{1}{7}$ is

A
$\frac{1}{42}$
B
$\frac{42}{41}$
C
$\frac{41}{42}$
D
$\frac{1}{12}$

Solution:

$\frac{1}{2} + \frac{1}{3} + \frac{1}{7} = \frac{21 + 14 + 6}{42} = \frac{41}{42}$

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