The symmetric form of the line passing through a point 1,0,3 and having direction ratios ⟨1,0,3⟩ is

A
$x - 1 = y = 3 (z - 3)$
B
$\frac{x - 1}{1} = \frac{y}{0} = \frac{z + 3}{3}$
C
$\frac{x - 1}{1} = \frac{y}{0} = \frac{z - 3}{3}$
D
$x - 1 = y = - 3 (z - 3)$

Solution:

The equation of a line which is passing through the point $(x_{1}, y_{1}, z_{1})$ and having direction ratios $⟨ a, b, c ⟩$ is $\frac{x - x_{1}}{a} = \frac{y - y_{1}}{b} = \frac{z - z_{1}}{c}$

Therefore, the equation of a line which is passing through the point $(1, 0, 3)$ and having direction ratios $⟨ 1, 0, 3 ⟩$ is $\frac{x - 1}{1} = \frac{y}{0} = \frac{z - 3}{3}$

The symmetric form of the line passing through a point $(1, 0, 3)$ and having direction ratios $⟨ 1, 0, 3 ⟩$ is

Solution:

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