The symmetric form of the line 2(x+1)=y=z+4

# The symmetric form of the line $2\left(x+1\right)=y=z+4$

1. A

$\frac{x-\left(-1\right)}{1}=\frac{y}{2}=\frac{z-\left(-4\right)}{2}$

2. B

$\frac{x-\left(-1\right)}{1}=\frac{y}{-2}=\frac{z-\left(-4\right)}{-2}$

3. C

$\frac{x-1}{1}=\frac{y}{2}=\frac{z-4}{2}$

4. D

$\frac{x+1}{0.5}=\frac{y}{1}=\frac{z+4}{2}$

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### Solution:

The symmetric form of any line is in the form of $\frac{x-{x}_{1}}{a}=\frac{y-{y}_{1}}{b}=\frac{z-{z}_{1}}{c}$

Therefore, the symmetric form of the given line is $\frac{x-\left(-1\right)}{1}=\frac{y}{2}=\frac{z-\left(-4\right)}{2}$

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