The symmetric form of the line 2(x+1)=y=z+4

The symmetric form of the line $2 (x + 1) = y = z + 4$

A
$\frac{x - (- 1)}{1} = \frac{y}{2} = \frac{z - (- 4)}{2}$
B
$\frac{x - (- 1)}{1} = \frac{y}{- 2} = \frac{z - (- 4)}{- 2}$
C
$\frac{x - 1}{1} = \frac{y}{2} = \frac{z - 4}{2}$
D
$\frac{x + 1}{0.5} = \frac{y}{1} = \frac{z + 4}{2}$

Solution:

The symmetric form of any line is in the form of $\frac{x - x_{1}}{a} = \frac{y - y_{1}}{b} = \frac{z - z_{1}}{c}$

Therefore, the symmetric form of the given line is $\frac{x - (- 1)}{1} = \frac{y}{2} = \frac{z - (- 4)}{2}$

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