MathematicsThe value of 1−sin2140°.sec140° is

The value of $\sqrt{1 - \sin^{2} 140 °} . \sec 140 °$ is

A
1
B
$- 1$
C
0
D
$- 2$

Solution:

$= \sqrt{1 - \sin^{2} 140 °} . \sec 140 °$

$= | \cos 140 ° | . \sec 140 °$

$= - \cos 140 ° . \sec 140 °$

$= - 1$

$| x | = - x$ If $x < 0$

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