The value of limx→0 x2sin⁡xtan⁡x , where [⋅] denotes the greatest integer function, is

The value of $lim_{x \to 0} [\frac{x^{2}}{\sin x \tan x}]$ , where $[\cdot]$ denotes the greatest integer function, is

A
0
B
1
C
limit does not exist
D
-1

Solution:

sinx < x < tanx
$\frac{x}{\tan x} < 1, \frac{x}{\sin x} > 1 \frac{x^{2}}{\sin x \tan x} < 1 \underset{x \to 0}{li m} [\frac{x^{2}}{\sin x \tan x}] = 0$

Related content

Karnataka Traditional Dress and Culture

Entrance Examinations in India

Maharashtra Traditional Dress for Men and Women

My Daily Routine Paragraph In English

Environment Pollution Paragraph for Students 100, 150, 200, 250 & 300 words

Past Perfect Continuous Tense

Patriotic Slogans by Freedom Fighters of India

GK Questions and Answers on Solar System

Past Perfect Tense

Healthy Food Slogans