The value of limx→0 x2sin⁡xtan⁡x , where [⋅] denotes the greatest integer function, is

The value of $lim_{x \to 0} [\frac{x^{2}}{\sin x \tan x}]$ , where $[\cdot]$ denotes the greatest integer function, is

A
0
B
1
C
limit does not exist
D
-1

Solution:

sinx < x < tanx
$\frac{x}{\tan x} < 1, \frac{x}{\sin x} > 1 \frac{x^{2}}{\sin x \tan x} < 1 \underset{x \to 0}{li m} [\frac{x^{2}}{\sin x \tan x}] = 0$

JEE Main 2023 Question Papers with Solutions

JEE Main 2024 Syllabus

Best Books for JEE Main 2024

JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria

JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria

JEE 2024: Exam Date, Syllabus, Eligibility Criteria

NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3

JEE Crash Course – JEE Crash Course 2023

NEET Crash Course – NEET Crash Course 2023

Solution:

Related content