The value of sin260°+cos260° is

A
1
B
0
C
2
D
$\frac{1}{\sqrt{2}}$

Solution:

We know that $\sin 60 ° = \frac{\sqrt{3}}{2}, \cos 60 ° = \frac{1}{2}$

Now

$\begin{array}{l} \sin^{2} 60 ° + \cos^{2} 60 ° = {(\frac{\sqrt{3}}{2})}^{2} + {(\frac{1}{2})}^{2} \\ = \frac{3}{4} + \frac{1}{4} \\ = \frac{3 + 1}{4} = \frac{4}{4} \\ = 1 \end{array}$

The value of $\sin^{2} 60 ° + \cos^{2} 60 °$ is

Solution:

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