The value of the integral  ∫−13 tan−1⁡xx2+1+tan−1⁡x2+1xdx is equal to 

The value of the integral  13tan1xx2+1+tan1x2+1xdx is equal to 

  1. A

    π

  2. B

    2π

  3. C

    4π

  4. D

    none of these 

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    Solution:

    We have,

    13tan1xx2+1+tan1x2+1xdx 

    =13tan1xx2+1+cot1xx2+1dx=13π2dx=2π

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