The value of limx→0 (1+sin⁡x)2cot⁡x, is 

The value of limx0(1+sinx)2cotx, is 

  1. A

    e

  2. B

    e2

  3. C

    e

  4. D

    none of these

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    Solution:

    We have,

    limx0(1+sinx)2cotx=elimx0sinx×2cotx=elimx02cosx=e2

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