The value of limx→0 1+sin⁡x−cos⁡x+log⁡(1−x)x3 is

The value of limx01+sinxcosx+log(1x)x3 is

  1. A

    1/2

  2. B

    1/2

  3. C

    0

  4. D

    1

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    Solution:

    We have,

    limx01+sinxcosx+log(1x)x3 =limx01+xx33!+x55!1x22!+x44!x66!+xx22x33x44x3=limx013!13+x215!15+=1613=12

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