The value oflimx→0 enx−1+nx+n22x2x3(n>0) is

The value of

limx0enx1+nx+n22x2x3(n>0) is

  1. A

    n26

  2. B

    n33

  3. C

    n36

  4. D

    1/6

    Fill Out the Form for Expert Academic Guidance!l



    +91



    Live ClassesBooksTest SeriesSelf Learning



    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    Using series expansion of enx the required
    limit is equal to

    limx0n36x3+n424x4+x3=n36

    Chat on WhatsApp Call Infinity Learn

      Talk to our academic expert!



      +91


      Live ClassesBooksTest SeriesSelf Learning




      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.