The value of limx→0 sin⁡xx1x2, is

The value of limx0sinxx1x2, is

  1. A

    e1/3

  2. B

    e1/3

  3. C

    e1/6

  4. D

    e1/6

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    Solution:

    We have,

    limx0sinxx1x2

    =limx0xx33!+x55!x77!+.1/x2

    =limx01x23!+x45!x67!+1x2

    =elimx01x2x23!+x45!x67!+    =e1/2!=e1/6                   

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