The value of limx→0 tan⁡π4+x1/x, is

The value of limx0tanπ4+x1/x, is

  1. A

    e

  2. B

    e2

  3. C

    2e

  4. D

    1e2

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    Solution:

    We have,

    limx0tanπ4+x1x=limx01+tanx1tanx1/x=limx01+2tanx1tanx1/x=elimx02tanx1tanx1x=elimx021tanx×tanxx =e2

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