The value of limx→0 x2+1−1×2+16−4 is

The value of $lim_{x \to 0} \frac{\sqrt{x^{2} + 1} - 1}{\sqrt{x^{2} + 16} - 4}$ is

A
3
B
4
C
1
D
2

Solution:

$\frac{\sqrt{x^{2} + 1} - 1}{\sqrt{x^{2} + 16} - 4} = \frac{x^{2} (\sqrt{x^{2} + 16} + 14)}{x^{2} (\sqrt{x^{2} + 1} + 1)},$ for $x \neq 0$

So the required limit $= \frac{4 + 4}{1 + 1} = 4$ .

Related content

Learning Beyond Boundaries: Rohit Sharma’s Vision for Accessible Education

Rohit Sharma: The Cricketer, The Icon – A Biography

ORS Full Form – Oral Rehydration Solution

SDO Full Form – Sub Divisional Officer

ESI Full Form – Employee State Insurance

NEET 2023 Result Date: Check Result, Download NEET UG Result PDF

ESIC Full Form – Employees’ State Insurance Corporation

OBC Full Form – Other Backward Classes

OK Full Form – Oll Korrect

ICDS Full Form – Integrated Child Development Services Scheme