The value of limx→∞ 3×2−1+2×2−14x+3 ,is 

The value of limx3x21+2x214x+3 ,is 

  1. A

    324

  2. B

    14(32)

  3. C

    322

  4. D

    none of these 

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    Solution:

    Dividing each term in the numerator and denominator by x, we get 

    limx3x21+2x214x+3=limx31/x2+21/x24+3/x=3+24=14(32)

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