The value of sin−1⁡(sin⁡10), is

A
10
B
$10 - 3 π$
C
$3 π - 10$
D
none of these

Solution:

We have,

$3 π < 10 < 3 π + \frac{π}{2}$

$\begin{array}{l} \Rightarrow 0 < 10 - 3 π < \frac{π}{2} \\ \Rightarrow - \frac{π}{2} < 3 π - 10 < 0 \Rightarrow \sin^{- 1} (\sin (3 π - 10)) = 3 π - 10 \end{array}$

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