The value of ∫sin⁡x+cos⁡x3+sin⁡2xdx, is 

The value of sinx+cosx3+sin2xdx, is 

  1. A

    14log2+sinxcosx2sinx+cosx+C

  2. B

    12log2+sinx2sinx+C

  3. C

    14log1+sinx1sinx+C

  4. D

    none of these

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    Solution:

    We have,

                I=sinx+cosx3+sin2xdx I=14(1sin2x)d(sinxcosx) I=122(sinxcosx)2d(sinxcosx) I=14log2+sinxcosx2sinx+cosx+C

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