MathematicsThe value of (x+8)2 is

The value of ${(x + 8)}^{2}$ is

A
$x^{2} + 6 x + 64$
B
$x^{2} - 6 x - 64$
C
$x^{2} - 6 x + 64$
D
$x^{2} + 6 x - 64$

Solution:

$\begin{array}{l} {(x + 8)}^{2} = x^{2} + 2 (x) (8) + 8^{2} \\ = x^{2} + 16 x + 64 \end{array}$

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