Three equal cubes are placed adjacently in a row. Find the ratio of the total surface area of the resulting cuboid to that of the sum of the total surface areas of the three cubes.

# Three equal cubes are placed adjacently in a row. Find the ratio of the total surface area of the resulting cuboid to that of the sum of the total surface areas of the three cubes.

1. A
2. B
3. C
4. D

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### Solution:

Total cubes= 3.
Suppose edge of each cube = x
Thus, one cube surface area
= $6{x}^{2}$
Three cubes surface area
= $3×6{x}^{2}=18{x}^{2}$
When cubes kept in a row,
Length (l) = $3x$
Breadth (b) = $x$
Height (h) = $x$
Now, surface area of this cuboid,

$=2×7{x}^{2}$

Ratio of both cubes,

Option 1 is Correct.

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