MathematicsTwo candidates were participating in an election. Of the total number of people in the electoral roll in that election, 10% did not use their votes and 60 votes were declared invalid. The winning candidate secured 47% of the total votes of the voter list and he won the election by 308 votes. How many votes were cast in that election?

Two candidates were participating in an election. Of the total number of people in the electoral roll in that election, 10% did not use their votes and 60 votes were declared invalid. The winning candidate secured 47% of the total votes of the voter list and he won the election by 308 votes. How many votes were cast in that election?


  1. A
    6200
  2. B
    5580
  3. C
    6000
  4. D
    7200 

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    Solution:

    Let the two candidates be A and B.
    Let the number of votes A get be x.
    Now, B, gets 308 less votes therefore B gets = x−308
    The total number of votes polled will be votes casted to A plus votes casted to B and then the 60 invalid votes:
    x+x−308+60=2x−248
    Given that 10% of the listed population refrained from voting , therefore 90% of the listed population took part in the election. Let the total population be P.
    90% of P = 2x−248
    P=2x-248×10090=20x-24809
    47% of this population voted for A , since A got a total of x votes , therefore:
    47% of 20x-24809 = x
    x = 2914
    The total numbers of votes polled are 2x−248, i.e. 5580.
      
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