Two cards are drawn without replacement from a well-shuffled pack. The probability that one of them is an ace of heart, is

A
$\frac{1}{25}$
B
$\frac{1}{26}$
C
$\frac{1}{52}$
D
None of these

Solution:

There are two conditions arise.
(i) When first is an ace of heart and second one is non-ace of heart, the probability $= \frac{1}{52} \times \frac{51}{51} = \frac{1}{52}$
(ii) When first is non-ace of heart and second one is an ace of heart, the probability $= \frac{51}{52} \times \frac{1}{51} = \frac{1}{52}$
.'. Required probability $= \frac{1}{52} + \frac{1}{52} = \frac{1}{26}$

Solution:

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