Two finite sets have m and n elements .The number of subsets of the first set is 112  more than that of the second set. The values of m and n are , respectively  

 Two finite sets have m and n elements .The number of subsets of the first set is 112  more than that of the second set. The values of m and n are , respectively  

  1. A

    4,7

  2. B

    7,4

  3. C

    4,4

     

  4. D

    7,7

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    Solution:

     We know, if any set has m elements, then the number of subsets is 2m.

    According to the given condition, we have 

    2m -2n = 112=16 × 7 2m -2n = 27 - 24

    On comparing both sides, we get  m =7 and n=4

     

     

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