Two lines L1:x=5,y3−α=z−2 and L2:x=α,y−1=z2−α are coplanar. Then α can take value(s)

Two lines L1:x=5,y3α=z2 and L2:x=α,y1=z2α are coplanar. Then α can take value(s)

  1. A

    1

  2. B

    2

  3. C

    3

  4. D

    4

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    Solution:

    L1:x50=y3α=z2

    L2:xa0=y1=z2α

    As L1,L2 are coplanar, therefore 5α0003α2012α=0

    (5α)65α+α22=0

    (5α)(α1)(α4)=0

    α=1,4,5

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