MathematicsTwo years ago, Mohit was three times as old as his son and two years hence, twice Mohit’s age will be equal to five times that of his son. Then the present age of Mohit is

Two years ago, Mohit was three times as old as his son and two years hence, twice Mohit's age will be equal to five times that of his son. Then the present age of Mohit is

A
14years
B
38years
C
32years
D
34years

Solution:

Let the Mohit’s son = x
2 years ago Mohit’s son age = x-2
Mohit age at that time =

Present age of Mohit

2 years hence Mohit’s age =

2 years hence son’s age =

According to the question

Present age of Mohit’s son = 14 years
Mohit Age = 38 years

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