MathematicsWithout calculating the cubes, find the value of -(0.4)3-(0.2)3+(0.6)3.

Without calculating the cubes, find the value of -(0.4)3-(0.2)3+(0.6)3.


  1. A
    0.144
  2. B
    0.4441
  3. C
    0.441
  4. D
    0.414 

    Fill Out the Form for Expert Academic Guidance!l



    +91



    Live ClassesBooksTest SeriesSelf Learning



    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    It is given -(0.4)3-(0.2)3+(0.6)3.
    We know the formula,
    x3+y3+z3-3xyz=(x+y+z)x2+y2+z2-xy-yz-zx and
    if (x+y+z)=0, then x3+y3+z3=3xyz.
    Rewriting the given expression as x = -0.4, y = -0.2, and z = 0.6,
    =-(0.4)3-(0.2)3+(0.6)3
    =3(-0.4)(-0.2)(0.6)
    =3(-0.4)(-0.12)
    =3(0.048)
    =0.144
    Hence, the value of -0.43-0.23+0.63=0.144.
    Therefore, option 1 is  correct.
     
    Chat on WhatsApp Call Infinity Learn

      Talk to our academic expert!



      +91


      Live ClassesBooksTest SeriesSelf Learning




      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.