MathematicsWrite the following cube in expanded form, 32x+13 .

Write the following cube in expanded form,


 32x+13 .


  1. A
    278x3+274x2-92x+1
  2. B
    278x3+274x2+92x+1
  3. C
    278x3+274x2+92x-1
  4. D
    278x3+274x2-92x-1 

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    Solution:

    It is given 32x+13.
    We know the algebraic identity,  a+b3=a3+b3+3aba+b.
    Applying identity a+b3=a3+b3+3aba+b in 32x+13, where, a=32x, and b = 1, we get,  32x+13=32x3+13+332x(1)32x+1
    32x+13=278x3+1+92x32x+1
    32x+13=278x3+1+92x×32x+92x
    32x+13=278x3+1+274x2+92x
    32x+13=278x3+274x2+92x+1
    Therefore, option 2 is  correct.
     
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