∫xx1+loge⁡xdx is equal to

xx1+logexdx is equal to

  1. A

    xxlogex+C

  2. B

    ex2+C

  3. C

    xx+C

  4. D

    none of these

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    Solution:

    We have,

    xx1+logexdx=1dxx=xx+C

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