Mathematicsy=x4+x2+1×2+x+1 then dydx=

$y = \frac{x^{4} + x^{2} + 1}{x^{2} + x + 1}$ then $\frac{d y}{d x} =$

A
$2 x - 1$
B
$2 x - 3$
C
$3 x - 2$
D
$4 x - 3$

Solution:

$\begin{array}{l} y = \frac{(x^{2} + x + 1) (x^{2} - x + 1)}{x^{2} + x + 1} \\ y = x^{2} - x + 1 \\ \frac{d y}{d x} = 2 x - 1 \end{array}$

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