PhysicsA 2kg block is placed over a 4kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 0.20. The acceleration of the two blocks if a horizontal force of 12N is applied to the lower block is g=10ms-2

A 2kg block is placed over a 4kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 0.20. The acceleration of the two blocks if a horizontal force of 12N is applied to the lower block is 

g=10ms-2

  1. A

    2 ms-2, 2 ms-2

  2. B

    2 ms-2, 1 ms-2

  3. C

    3 ms-2, 1 ms-2

  4. D

    4 ms-2, 1 ms-2

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    Solution:

    The maximum frictional force between the blocks

    f=0.2(20)=4N

    So, the lower block will move with an acceleration 1ms-2.

    for upper block.

    a=F-fm=12-42=4ms-2

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