A ball projected vertically upward with a speed of 50 ms-1. Then the speed at half of the maximum height is :(g= 10 m/s2)

# A ball projected vertically upward with a speed of 50 ms-1. Then the speed at half of the maximum height is :(g= 10 m/s2)

1. A

100 ms-1

2. B

125 ms-1

3. C

35 ms-1

4. D

45 ms-1

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### Solution:

Since a ball is thrown vertically upward,
Initial velocity= 50 m/s
Final velocity once the ball reaches the maximum height= 0 m/s

we know,
(Acceleration is negative since the ball is going against gravity)

Where s is the displacement = maximum height(h)

The speed at the half of maximum height will be:

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