A body executes SHM with an amplitude A. At what displacement from the mean position is the potential energy of the body one-fourth of its total energy

A body executes SHM with an amplitude A. At what displacement from the mean position is the potential energy of the body one-fourth of its total energy

A
A/4
B
A/2
C
3A/4
D
Some other fraction of A

Solution:

$\frac{1}{2} {mω}^{2} y^{2} = \frac{1}{4} (\frac{1}{2} {mω}^{2} A^{2}) \Rightarrow y = \frac{A}{2}$

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