A body falls for 5s from rest. If the acceleration due to the gravity of earth ceases to act, The distance travels in the next 3s is.

# A body falls for 5s from rest. If the acceleration due to the gravity of earth ceases to act, The distance travels in the next 3s is.

1. A

73.5 m

2. B

294 m

3. C

147 m

4. D

49 m

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### Solution:

Initially, the body starts its motion from rest therefore, u=0
Velocity v,  when the object falls for 5 seconds before acceleration due to gravity is ceased:
v=u+at
=0+9.8×5=49m/s

Just before the acceleration stops acting the velocity of the body is 49m/s
Now the distance travelled by the body in the next 3s
Now, g= 0 m/s

$\mathrm{s}=\mathrm{ut}+\frac{1}{2}{\mathrm{gt}}^{2}$
$49×3+\frac{1}{2}×0×{\mathrm{t}}^{2}$
= 49 x 3 = 147 m

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