A bomb projected from ground at an angle θθ≠90° with horizontal explodes into two fragments of equal mass at top most point of  its trajectory. If one of the fragment returns to point of projection then ratio of  de-Broglie wavelength of second fragment just after explosion to bomb just before explosion is 

A bomb projected from ground at an angle θθ90° with horizontal explodes into two fragments of equal mass at top most point of  its trajectory. If one of the fragment returns to point of projection then ratio of  de-Broglie wavelength of second fragment just after explosion to bomb just before explosion is 

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    Solution:

    From the law of conservation of momentum

    mucosθ=m2ucosθ+m2v1v1=3ucosθ(1)λD=hmv(2)

    The ratio of De-Broglie wavelength

    λD2λD=hm23ucosθhmucosθ=23

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