PhysicsA bulb contains one mole of hydrogen mixed with one mole of oxygen at temperature T. The ratio of r.m.s. values of velocity of hydrogen molecules to that of oxygen molecules, is

A bulb contains one mole of hydrogen mixed with one mole of oxygen at temperature T. The ratio of r.m.s. values of velocity of hydrogen molecules to that of oxygen molecules, is

A
4 : 1
B
1 : 16
C
1 : 4
D
16 : 1

Solution:

$V \propto \frac{1}{\sqrt{M}} \Rightarrow \frac{V_{H}}{V_{O}} = \sqrt{\frac{M_{O 2}}{M_{H}}} = \sqrt{\frac{32}{2}} = \frac{4}{1}$

because $V_{r m s} = \sqrt{\frac{3 R T}{M}}$

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