PhysicsA bullet moving with a uniform velocity v, stops suddenly after hitting the target and the whole mass melts. Let mass be m, specific heat S, initial temperature 25°C, melting point 475°C and the latent heat l. Then v is given by

A bullet moving with a uniform velocity v, stops suddenly after hitting the target and the whole mass melts. Let mass be m, specific heat S, initial temperature 25°C, melting point 475°C and the latent heat l. Then v is given by

  1. A

    mL=mS(47525)+12mv2J

  2. B

    mS(47525)+mL=mv22J

  3. C

    mS(47525)+mL=mv2J

  4. D

    mS(47525)mL=mv22J

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    Solution:

    Firstly the temperature of bullet rises up to melting point, then it melts. Hence according to W=JH.

    12mv2=J.[m.c.Δθ+mL]=J[mS(47525)+mL]

    mS(47525)+mL=mv22J

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