A capacitor of capacity C1  is charged to the potential of V0 . On disconnecting from the battery, it is connected with a capacitor of capacity C2 as shown in the adjoining figure. The ratio of energies of system of capacitors before and after the connection of switch  ‘S’ will be 

A capacitor of capacity C1  is charged to the potential of V0 . On disconnecting from the battery, it is connected with a capacitor of capacity C2 as shown in the adjoining figure. The ratio of energies of system of capacitors before and after the connection of switch  ‘S’ will be
 

  1. A

    C1+C2/C1

  2. B

    C1/C1+C2

  3. C

    C1C2

  4. D

    C1/C2

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    Solution:

    Given Capacity of capacitor  =C1,C2
    Potential  V1=V0
    We know that Common potential  V=C1V1+C2V2C1+C2
    Common potential,  V=C1V0+0C1+C2=C1V0C1+C2
    We know potential energy stored in capacitor, 
    U=12CV2
    Now  UiUf=12C1V0212C1+C2V2=C1+C2C1
    Therefore, the correct answer is (A)
     

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