PhysicsA car weighing 10 g is initially moving with a velocity of 50 m/s. On applying a constant force on the ball for 2 s, it acquires a velocity of 70 m/s. The rate of change of momentum is ____ N.

A car weighing 10 g is initially moving with a velocity of 50 m/s. On applying a constant force on the ball for 2 s, it acquires a velocity of 70 m/s. The rate of change of momentum is ____ N.


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    Solution:

    A car weighing 10 g is initially moving with a velocity of 50 m/s. On applying a constant force on the ball for 2 s, it acquires a velocity of 70 m/s.  The rate of change of momentum is 0.1
    Given that,
    Mass (m) = 10 g
    Initial velocity (u) = 50 m/as its car started.
    Final velocity (v) = 70 m/s
    Time (t) = 2 sec
    From the relation of momentum, mass and velocity
    Initial momentum = 10/1000 × 50= 0.5 kg m/
    Final momentum = 10/1000 ×70 = 0.7 kg m/
    Rate of change of momentum=final momentum-initial momentum time taken
    =00.7-00.520
    = 0.1N
     
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